5034311300403 has 160 divisors (see below), whose sum is σ = 9666110361600. Its totient is φ = 2588250309120.

The previous prime is 5034311300401. The next prime is 5034311300453. The reversal of 5034311300403 is 3040031134305.

5034311300403 is a `hidden beast` number, since 5 + 0 + 3 + 4 + 311 + 300 + 40 + 3 = 666.

5034311300403 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 5034311300403 - 2¹ = 5034311300401 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is not an unprimeable number, because it can be changed into a prime (5034311300401) by changing a digit.

It is a polite number, since it can be written in 159 ways as a sum of consecutive naturals, for example, 29559550 + ... + 29729372.

It is an arithmetic number, because the mean of its divisors is an integer number (60413189760).

Almost surely, 2^{5034311300403} is an apocalyptic number.

5034311300403 is a deficient number, since it is larger than the sum of its proper divisors (4631799061197).

5034311300403 is a wasteful number, since it uses less digits than its factorization.

5034311300403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 169964 (or 169941 counting only the distinct ones).

The product of its (nonzero) digits is 6480, while the sum is 27.

Adding to 5034311300403 its reverse (3040031134305), we get a palindrome (8074342434708).

The spelling of 5034311300403 in words is "five trillion, thirty-four billion, three hundred eleven million, three hundred thousand, four hundred three".