Base | Representation |
---|---|
bin | 100100101000010011010… |
… | …1101110000101101010011 |
3 | 122211021112120221221120212 |
4 | 1021100212231300231103 |
5 | 1124440322401413412 |
6 | 14412425441554335 |
7 | 1026501626103404 |
oct | 111204655605523 |
9 | 18737476857525 |
10 | 5034351201107 |
11 | 167106900a368 |
12 | 6938360459ab |
13 | 2a6977a64877 |
14 | 135941a459ab |
15 | 8ae4d345222 |
hex | 49426b70b53 |
5034351201107 has 2 divisors, whose sum is σ = 5034351201108. Its totient is φ = 5034351201106.
The previous prime is 5034351201101. The next prime is 5034351201157. The reversal of 5034351201107 is 7011021534305.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5034351201107 - 212 = 5034351197011 is a prime.
It is a super-4 number, since 4×50343512011074 (a number of 52 digits) contains 4444 as substring.
It is not a weakly prime, because it can be changed into another prime (5034351201101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2517175600553 + 2517175600554.
It is an arithmetic number, because the mean of its divisors is an integer number (2517175600554).
Almost surely, 25034351201107 is an apocalyptic number.
5034351201107 is a deficient number, since it is larger than the sum of its proper divisors (1).
5034351201107 is an equidigital number, since it uses as much as digits as its factorization.
5034351201107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12600, while the sum is 32.
The spelling of 5034351201107 in words is "five trillion, thirty-four billion, three hundred fifty-one million, two hundred one thousand, one hundred seven".
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