Base | Representation |
---|---|
bin | 100100101000010101011… |
… | …0110001010010110010111 |
3 | 122211021201102101022110120 |
4 | 1021100222312022112113 |
5 | 1124440443122342101 |
6 | 14412440355323023 |
7 | 1026503430200412 |
oct | 111205266122627 |
9 | 18737642338416 |
10 | 5034420512151 |
11 | 16710a414a818 |
12 | 6938552b0473 |
13 | 2a6989221914 |
14 | 13594ad28b79 |
15 | 8ae54486b36 |
hex | 4942ad8a597 |
5034420512151 has 32 divisors (see below), whose sum is σ = 6850471320000. Its totient is φ = 3287536631808.
The previous prime is 5034420512113. The next prime is 5034420512171. The reversal of 5034420512151 is 1512150244305.
It is not a de Polignac number, because 5034420512151 - 215 = 5034420479383 is a prime.
It is a super-3 number, since 3×50344205121513 (a number of 39 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5034420512171) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 495070195 + ... + 495080363.
It is an arithmetic number, because the mean of its divisors is an integer number (214077228750).
Almost surely, 25034420512151 is an apocalyptic number.
5034420512151 is a deficient number, since it is larger than the sum of its proper divisors (1816050807849).
5034420512151 is a wasteful number, since it uses less digits than its factorization.
5034420512151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15043.
The product of its (nonzero) digits is 24000, while the sum is 33.
Adding to 5034420512151 its reverse (1512150244305), we get a palindrome (6546570756456).
The spelling of 5034420512151 in words is "five trillion, thirty-four billion, four hundred twenty million, five hundred twelve thousand, one hundred fifty-one".
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