Base | Representation |
---|---|
bin | 1001011000001001… |
… | …11000010101100101 |
3 | 110222212012021000211 |
4 | 10230010320111211 |
5 | 40302304203013 |
6 | 2151321335421 |
7 | 235521032455 |
oct | 45404702545 |
9 | 13885167024 |
10 | 5034444133 |
11 | 21538a3434 |
12 | b86037571 |
13 | 62302b634 |
14 | 35a8a9d65 |
15 | 1e6eac23d |
hex | 12c138565 |
5034444133 has 2 divisors, whose sum is σ = 5034444134. Its totient is φ = 5034444132.
The previous prime is 5034444091. The next prime is 5034444143. The reversal of 5034444133 is 3314444305.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2972648484 + 2061795649 = 54522^2 + 45407^2 .
It is a cyclic number.
It is not a de Polignac number, because 5034444133 - 29 = 5034443621 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5034444095 and 5034444104.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5034444143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2517222066 + 2517222067.
It is an arithmetic number, because the mean of its divisors is an integer number (2517222067).
Almost surely, 25034444133 is an apocalyptic number.
It is an amenable number.
5034444133 is a deficient number, since it is larger than the sum of its proper divisors (1).
5034444133 is an equidigital number, since it uses as much as digits as its factorization.
5034444133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 34560, while the sum is 31.
The square root of 5034444133 is about 70953.8169022640. The cubic root of 5034444133 is about 1713.8935404550.
Adding to 5034444133 its reverse (3314444305), we get a palindrome (8348888438).
The spelling of 5034444133 in words is "five billion, thirty-four million, four hundred forty-four thousand, one hundred thirty-three".
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