Base | Representation |
---|---|
bin | 1001011000001110… |
… | …11001100010110001 |
3 | 110222220102210210101 |
4 | 10230013121202301 |
5 | 40302441320213 |
6 | 2151343432401 |
7 | 235526452522 |
oct | 45407314261 |
9 | 13886383711 |
10 | 5035104433 |
11 | 2154204537 |
12 | b862b5701 |
13 | 623200048 |
14 | 35a9dc849 |
15 | 1e708cbdd |
hex | 12c1d98b1 |
5035104433 has 2 divisors, whose sum is σ = 5035104434. Its totient is φ = 5035104432.
The previous prime is 5035104397. The next prime is 5035104461. The reversal of 5035104433 is 3344015305.
It is an a-pointer prime, because the next prime (5035104461) can be obtained adding 5035104433 to its sum of digits (28).
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4852097649 + 183006784 = 69657^2 + 13528^2 .
It is a cyclic number.
It is not a de Polignac number, because 5035104433 - 29 = 5035103921 is a prime.
It is not a weakly prime, because it can be changed into another prime (5035104493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2517552216 + 2517552217.
It is an arithmetic number, because the mean of its divisors is an integer number (2517552217).
Almost surely, 25035104433 is an apocalyptic number.
It is an amenable number.
5035104433 is a deficient number, since it is larger than the sum of its proper divisors (1).
5035104433 is an equidigital number, since it uses as much as digits as its factorization.
5035104433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10800, while the sum is 28.
The square root of 5035104433 is about 70958.4697763417. The cubic root of 5035104433 is about 1713.9684665973.
Adding to 5035104433 its reverse (3344015305), we get a palindrome (8379119738).
The spelling of 5035104433 in words is "five billion, thirty-five million, one hundred four thousand, four hundred thirty-three".
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