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503512540505497 is a prime number
BaseRepresentation
bin111001001111100010010011…
…0000111011110010110011001
32110000210022212200020022121201
41302133010212013132112121
51011444022140332133442
64542514245015034201
7211025403065554015
oct16237044607362631
92400708780208551
10503512540505497
11136486518630376
124858012b06b961
13187c504b470bc3
148c4a1cbc91545
153d327b3bb07b7
hex1c9f1261de599

503512540505497 has 2 divisors, whose sum is σ = 503512540505498. Its totient is φ = 503512540505496.

The previous prime is 503512540505411. The next prime is 503512540505549. The reversal of 503512540505497 is 794505045215305.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 415829748745216 + 87682791760281 = 20391904^2 + 9363909^2 .

It is a cyclic number.

It is not a de Polignac number, because 503512540505497 - 223 = 503512532116889 is a prime.

It is not a weakly prime, because it can be changed into another prime (503512540505407) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 251756270252748 + 251756270252749.

It is an arithmetic number, because the mean of its divisors is an integer number (251756270252749).

Almost surely, 2503512540505497 is an apocalyptic number.

It is an amenable number.

503512540505497 is a deficient number, since it is larger than the sum of its proper divisors (1).

503512540505497 is an equidigital number, since it uses as much as digits as its factorization.

503512540505497 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18900000, while the sum is 55.

The spelling of 503512540505497 in words is "five hundred three trillion, five hundred twelve billion, five hundred forty million, five hundred five thousand, four hundred ninety-seven".