Base | Representation |
---|---|
bin | 100100101000101101101… |
… | …0110100110100000111011 |
3 | 122211100211010201011101021 |
4 | 1021101123112212200323 |
5 | 1124444124441304431 |
6 | 14413053230203311 |
7 | 1026532541363332 |
oct | 111213326464073 |
9 | 18740733634337 |
10 | 5035234322491 |
11 | 167148156354a |
12 | 693a41953537 |
13 | 2a6a889cb7b9 |
14 | 1359c704ad19 |
15 | 8aea0b3ab11 |
hex | 4945b5a683b |
5035234322491 has 2 divisors, whose sum is σ = 5035234322492. Its totient is φ = 5035234322490.
The previous prime is 5035234322441. The next prime is 5035234322519. The reversal of 5035234322491 is 1942234325305.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5035234322491 - 211 = 5035234320443 is a prime.
It is not a weakly prime, because it can be changed into another prime (5035234322411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2517617161245 + 2517617161246.
It is an arithmetic number, because the mean of its divisors is an integer number (2517617161246).
Almost surely, 25035234322491 is an apocalyptic number.
5035234322491 is a deficient number, since it is larger than the sum of its proper divisors (1).
5035234322491 is an equidigital number, since it uses as much as digits as its factorization.
5035234322491 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 777600, while the sum is 43.
Adding to 5035234322491 its reverse (1942234325305), we get a palindrome (6977468647796).
The spelling of 5035234322491 in words is "five trillion, thirty-five billion, two hundred thirty-four million, three hundred twenty-two thousand, four hundred ninety-one".
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