Base | Representation |
---|---|
bin | 100100101000101101101… |
… | …0111000001100000010101 |
3 | 122211100211010220210000212 |
4 | 1021101123113001200111 |
5 | 1124444130003324140 |
6 | 14413053232415205 |
7 | 1026532542333545 |
oct | 111213327014025 |
9 | 18740733823025 |
10 | 5035234433045 |
11 | 1671481629613 |
12 | 693a419a7505 |
13 | 2a6a88a39c0b |
14 | 1359c7079325 |
15 | 8aea0b5d765 |
hex | 4945b5c1815 |
5035234433045 has 32 divisors (see below), whose sum is σ = 6358968944640. Its totient is φ = 3822231179520.
The previous prime is 5035234433029. The next prime is 5035234433057. The reversal of 5035234433045 is 5403344325305.
5035234433045 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 5035234433045 - 24 = 5035234433029 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 5035234432993 and 5035234433011.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 12610607 + ... + 13003763.
It is an arithmetic number, because the mean of its divisors is an integer number (198717779520).
Almost surely, 25035234433045 is an apocalyptic number.
It is an amenable number.
5035234433045 is a deficient number, since it is larger than the sum of its proper divisors (1323734511595).
5035234433045 is a wasteful number, since it uses less digits than its factorization.
5035234433045 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 394805.
The product of its (nonzero) digits is 1296000, while the sum is 41.
The spelling of 5035234433045 in words is "five trillion, thirty-five billion, two hundred thirty-four million, four hundred thirty-three thousand, forty-five".
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