Base | Representation |
---|---|
bin | 100100101000101101101… |
… | …0111000011110001101111 |
3 | 122211100211010221020210112 |
4 | 1021101123113003301233 |
5 | 1124444130004123401 |
6 | 14413053232530235 |
7 | 1026532542402641 |
oct | 111213327036157 |
9 | 18740733836715 |
10 | 5035234442351 |
11 | 1671481635603 |
12 | 693a419b097b |
13 | 2a6a88a41219 |
14 | 1359c707c891 |
15 | 8aea0b613bb |
hex | 4945b5c3c6f |
5035234442351 has 2 divisors, whose sum is σ = 5035234442352. Its totient is φ = 5035234442350.
The previous prime is 5035234442333. The next prime is 5035234442377. The reversal of 5035234442351 is 1532444325305.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5035234442351 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5035234442299 and 5035234442308.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5035234442851) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2517617221175 + 2517617221176.
It is an arithmetic number, because the mean of its divisors is an integer number (2517617221176).
Almost surely, 25035234442351 is an apocalyptic number.
5035234442351 is a deficient number, since it is larger than the sum of its proper divisors (1).
5035234442351 is an equidigital number, since it uses as much as digits as its factorization.
5035234442351 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 864000, while the sum is 41.
Adding to 5035234442351 its reverse (1532444325305), we get a palindrome (6567678767656).
The spelling of 5035234442351 in words is "five trillion, thirty-five billion, two hundred thirty-four million, four hundred forty-two thousand, three hundred fifty-one".
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