Base | Representation |
---|---|
bin | 1110101001111100011… |
… | …10010011110010110001 |
3 | 1210010202121210010020112 |
4 | 13110332032103302301 |
5 | 31222240102041423 |
6 | 1023155141351105 |
7 | 51244364554604 |
oct | 7247616236261 |
9 | 1703677703215 |
10 | 503555112113 |
11 | 184613807889 |
12 | 81713708495 |
13 | 3863c842601 |
14 | 1a52d44a33b |
15 | d172cc9a78 |
hex | 753e393cb1 |
503555112113 has 2 divisors, whose sum is σ = 503555112114. Its totient is φ = 503555112112.
The previous prime is 503555112077. The next prime is 503555112119. The reversal of 503555112113 is 311211555305.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 503542094449 + 13017664 = 709607^2 + 3608^2 .
It is a cyclic number.
It is not a de Polignac number, because 503555112113 - 228 = 503286676657 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 503555112113.
It is not a weakly prime, because it can be changed into another prime (503555112119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 251777556056 + 251777556057.
It is an arithmetic number, because the mean of its divisors is an integer number (251777556057).
Almost surely, 2503555112113 is an apocalyptic number.
It is an amenable number.
503555112113 is a deficient number, since it is larger than the sum of its proper divisors (1).
503555112113 is an equidigital number, since it uses as much as digits as its factorization.
503555112113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11250, while the sum is 32.
Adding to 503555112113 its reverse (311211555305), we get a palindrome (814766667418).
The spelling of 503555112113 in words is "five hundred three billion, five hundred fifty-five million, one hundred twelve thousand, one hundred thirteen".
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