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50390354341 is a prime number
BaseRepresentation
bin101110111011011111…
…111100100110100101
311211001210100020010001
4232323133330212211
51311144412314331
635052104101301
73432501642025
oct567337744645
9154053306101
1050390354341
111a409050048
129923764831
1349a08b4b22
142620503a85
15149dca0561
hexbbb7fc9a5

50390354341 has 2 divisors, whose sum is σ = 50390354342. Its totient is φ = 50390354340.

The previous prime is 50390354327. The next prime is 50390354407. The reversal of 50390354341 is 14345309305.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 47405917441 + 2984436900 = 217729^2 + 54630^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-50390354341 is a prime.

It is a super-2 number, since 2×503903543412 (a number of 22 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 50390354341.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (50390355341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25195177170 + 25195177171.

It is an arithmetic number, because the mean of its divisors is an integer number (25195177171).

Almost surely, 250390354341 is an apocalyptic number.

It is an amenable number.

50390354341 is a deficient number, since it is larger than the sum of its proper divisors (1).

50390354341 is an equidigital number, since it uses as much as digits as its factorization.

50390354341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 97200, while the sum is 37.

The spelling of 50390354341 in words is "fifty billion, three hundred ninety million, three hundred fifty-four thousand, three hundred forty-one".