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50391843613 is a prime number
BaseRepresentation
bin101110111011100101…
…101000001100011101
311211001220010220000021
4232323211220030131
51311200302443423
635052200032141
73432520413646
oct567345501435
9154056126007
1050391843613
111a409977a51
129924162651
1349a0cb6957
1426207b06cd
15149de9695d
hexbbb96831d

50391843613 has 2 divisors, whose sum is σ = 50391843614. Its totient is φ = 50391843612.

The previous prime is 50391843569. The next prime is 50391843653. The reversal of 50391843613 is 31634819305.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 45572429529 + 4819414084 = 213477^2 + 69422^2 .

It is a cyclic number.

It is not a de Polignac number, because 50391843613 - 225 = 50358289181 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 50391843613.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (50391843653) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25195921806 + 25195921807.

It is an arithmetic number, because the mean of its divisors is an integer number (25195921807).

Almost surely, 250391843613 is an apocalyptic number.

It is an amenable number.

50391843613 is a deficient number, since it is larger than the sum of its proper divisors (1).

50391843613 is an equidigital number, since it uses as much as digits as its factorization.

50391843613 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 233280, while the sum is 43.

The spelling of 50391843613 in words is "fifty billion, three hundred ninety-one million, eight hundred forty-three thousand, six hundred thirteen".