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50401612813 is a prime number
BaseRepresentation
bin101110111100001010…
…111001010000001101
311211002120112012211111
4232330022321100031
51311210303102223
635053145252021
73432666432406
oct567412712015
9154076465744
1050401612813
111a41443a772
129927494011
1349a3027446
142621bd49ad
15149ec7630d
hexbbc2b940d

50401612813 has 2 divisors, whose sum is σ = 50401612814. Its totient is φ = 50401612812.

The previous prime is 50401612799. The next prime is 50401612819. The reversal of 50401612813 is 31821610405.

50401612813 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 44904576649 + 5497036164 = 211907^2 + 74142^2 .

It is a cyclic number.

It is not a de Polignac number, because 50401612813 - 233 = 41811678221 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (50401612819) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25200806406 + 25200806407.

It is an arithmetic number, because the mean of its divisors is an integer number (25200806407).

Almost surely, 250401612813 is an apocalyptic number.

It is an amenable number.

50401612813 is a deficient number, since it is larger than the sum of its proper divisors (1).

50401612813 is an equidigital number, since it uses as much as digits as its factorization.

50401612813 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5760, while the sum is 31.

The spelling of 50401612813 in words is "fifty billion, four hundred one million, six hundred twelve thousand, eight hundred thirteen".