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504032143253117 is a prime number
BaseRepresentation
bin111001010011010100010000…
…0110110101001111001111101
32110002122000001200110210021212
41302212220200312221321331
51012031030312133044432
64543553100421134205
7211111056244211153
oct16246504066517175
92402560050423255
10504032143253117
11136666916859236
1248644980b5a365
13188320478a780b
148c6740070d3d3
153d410757402b2
hex1ca6a20da9e7d

504032143253117 has 2 divisors, whose sum is σ = 504032143253118. Its totient is φ = 504032143253116.

The previous prime is 504032143253077. The next prime is 504032143253213. The reversal of 504032143253117 is 711352341230405.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 257505278274841 + 246526864978276 = 16046971^2 + 15701174^2 .

It is a cyclic number.

It is not a de Polignac number, because 504032143253117 - 232 = 504027848285821 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (504032143258117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 252016071626558 + 252016071626559.

It is an arithmetic number, because the mean of its divisors is an integer number (252016071626559).

Almost surely, 2504032143253117 is an apocalyptic number.

It is an amenable number.

504032143253117 is a deficient number, since it is larger than the sum of its proper divisors (1).

504032143253117 is an equidigital number, since it uses as much as digits as its factorization.

504032143253117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 302400, while the sum is 41.

The spelling of 504032143253117 in words is "five hundred four trillion, thirty-two billion, one hundred forty-three million, two hundred fifty-three thousand, one hundred seventeen".