Base | Representation |
---|---|
bin | 100100101011100000111… |
… | …1100001000011100111001 |
3 | 122211221100102000202221121 |
4 | 1021113001330020130321 |
5 | 1130043440100413103 |
6 | 14415530215505241 |
7 | 1030134612261115 |
oct | 111270174103471 |
9 | 18757312022847 |
10 | 5041250404153 |
11 | 1673a89478767 |
12 | 695040688221 |
13 | 2a7507208332 |
14 | 135dd8044745 |
15 | 8b203d9d6bd |
hex | 495c1f08739 |
5041250404153 has 2 divisors, whose sum is σ = 5041250404154. Its totient is φ = 5041250404152.
The previous prime is 5041250404111. The next prime is 5041250404261. The reversal of 5041250404153 is 3514040521405.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4321625637904 + 719624766249 = 2078852^2 + 848307^2 .
It is a cyclic number.
It is not a de Polignac number, because 5041250404153 - 221 = 5041248307001 is a prime.
It is not a weakly prime, because it can be changed into another prime (5041250404453) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2520625202076 + 2520625202077.
It is an arithmetic number, because the mean of its divisors is an integer number (2520625202077).
Almost surely, 25041250404153 is an apocalyptic number.
It is an amenable number.
5041250404153 is a deficient number, since it is larger than the sum of its proper divisors (1).
5041250404153 is an equidigital number, since it uses as much as digits as its factorization.
5041250404153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48000, while the sum is 34.
Adding to 5041250404153 its reverse (3514040521405), we get a palindrome (8555290925558).
The spelling of 5041250404153 in words is "five trillion, forty-one billion, two hundred fifty million, four hundred four thousand, one hundred fifty-three".
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