Base | Representation |
---|---|
bin | 100100101011100010110… |
… | …0011110011101010110111 |
3 | 122211221111122022021222112 |
4 | 1021113011203303222313 |
5 | 1130044101122331224 |
6 | 14415540225321235 |
7 | 1030136250425144 |
oct | 111270543635267 |
9 | 18757448267875 |
10 | 5041311136439 |
11 | 167400a789836 |
12 | 695058a9621b |
13 | 2a75169806b6 |
14 | 1360021333cb |
15 | 8b20939830e |
hex | 495c58f3ab7 |
5041311136439 has 2 divisors, whose sum is σ = 5041311136440. Its totient is φ = 5041311136438.
The previous prime is 5041311136391. The next prime is 5041311136471. The reversal of 5041311136439 is 9346311131405.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5041311136439 - 240 = 3941799508663 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5041311136396 and 5041311136405.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5041311136139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2520655568219 + 2520655568220.
It is an arithmetic number, because the mean of its divisors is an integer number (2520655568220).
Almost surely, 25041311136439 is an apocalyptic number.
5041311136439 is a deficient number, since it is larger than the sum of its proper divisors (1).
5041311136439 is an equidigital number, since it uses as much as digits as its factorization.
5041311136439 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 116640, while the sum is 41.
The spelling of 5041311136439 in words is "five trillion, forty-one billion, three hundred eleven million, one hundred thirty-six thousand, four hundred thirty-nine".
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