Base | Representation |
---|---|
bin | 100100101011100011101… |
… | …0010101110101101011011 |
3 | 122211221120200000121001012 |
4 | 1021113013102232231123 |
5 | 1130044131043322412 |
6 | 14415543144444135 |
7 | 1030140052532531 |
oct | 111270722565533 |
9 | 18757520017035 |
10 | 5041340214107 |
11 | 167402513a26a |
12 | 69506677964b |
13 | 2a751c9c1912 |
14 | 136005d42151 |
15 | 8b20bbddc22 |
hex | 495c74aeb5b |
5041340214107 has 2 divisors, whose sum is σ = 5041340214108. Its totient is φ = 5041340214106.
The previous prime is 5041340214091. The next prime is 5041340214121. The reversal of 5041340214107 is 7014120431405.
5041340214107 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5041340214107 - 24 = 5041340214091 is a prime.
It is a super-2 number, since 2×50413402141072 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5041340214167) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2520670107053 + 2520670107054.
It is an arithmetic number, because the mean of its divisors is an integer number (2520670107054).
Almost surely, 25041340214107 is an apocalyptic number.
5041340214107 is a deficient number, since it is larger than the sum of its proper divisors (1).
5041340214107 is an equidigital number, since it uses as much as digits as its factorization.
5041340214107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13440, while the sum is 32.
The spelling of 5041340214107 in words is "five trillion, forty-one billion, three hundred forty million, two hundred fourteen thousand, one hundred seven".
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