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5041352221183 is a prime number
BaseRepresentation
bin100100101011100100000…
…0000100010000111111111
3122211221121111121121122201
41021113020000202013333
51130044142132034213
614415544254052331
71030140256561555
oct111271000420777
918757544547581
105041352221183
1116740309a0373
1269506a7aa0a7
132a7522336bb5
14136007789bd5
158b20ccb16dd
hex495c80221ff

5041352221183 has 2 divisors, whose sum is σ = 5041352221184. Its totient is φ = 5041352221182.

The previous prime is 5041352221099. The next prime is 5041352221219. The reversal of 5041352221183 is 3811222531405.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5041352221183 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5041352621183) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2520676110591 + 2520676110592.

It is an arithmetic number, because the mean of its divisors is an integer number (2520676110592).

Almost surely, 25041352221183 is an apocalyptic number.

5041352221183 is a deficient number, since it is larger than the sum of its proper divisors (1).

5041352221183 is an equidigital number, since it uses as much as digits as its factorization.

5041352221183 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 57600, while the sum is 37.

Adding to 5041352221183 its reverse (3811222531405), we get a palindrome (8852574752588).

The spelling of 5041352221183 in words is "five trillion, forty-one billion, three hundred fifty-two million, two hundred twenty-one thousand, one hundred eighty-three".