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504144312134 = 2252072156067
BaseRepresentation
bin1110101011000010101…
…01111011011101000110
31210012021200110120201112
413111201111323131012
531224441420442014
61023333430125022
751265110643121
oct7254125733506
91705250416645
10504144312134
11184896359551
1281858ab0772
1338704929488
141a5877c13b8
15d1a98b273e
hex756157b746

504144312134 has 4 divisors (see below), whose sum is σ = 756216468204. Its totient is φ = 252072156066.

The previous prime is 504144312101. The next prime is 504144312151. The reversal of 504144312134 is 431213441405.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×5041443121342 (a number of 24 digits) contains 22 as substring.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 504144312134.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126036078032 + ... + 126036078035.

It is an arithmetic number, because the mean of its divisors is an integer number (189054117051).

Almost surely, 2504144312134 is an apocalyptic number.

504144312134 is a deficient number, since it is larger than the sum of its proper divisors (252072156070).

504144312134 is a wasteful number, since it uses less digits than its factorization.

504144312134 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 252072156069.

The product of its (nonzero) digits is 23040, while the sum is 32.

Adding to 504144312134 its reverse (431213441405), we get a palindrome (935357753539).

The spelling of 504144312134 in words is "five hundred four billion, one hundred forty-four million, three hundred twelve thousand, one hundred thirty-four".

Divisors: 1 2 252072156067 504144312134