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504214155113 is a prime number
BaseRepresentation
bin1110101011001011000…
…00010110111101101001
31210012110112212222021112
413111211200112331221
531230112310430423
61023344403120105
751266616414014
oct7254540267551
91705415788245
10504214155113
11184921822619
1281878373035
1338716241696
141a592ba237b
15d1b0aaba78
hex7565816f69

504214155113 has 2 divisors, whose sum is σ = 504214155114. Its totient is φ = 504214155112.

The previous prime is 504214155083. The next prime is 504214155119. The reversal of 504214155113 is 311551412405.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 274085755024 + 230128400089 = 523532^2 + 479717^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-504214155113 is a prime.

It is a super-3 number, since 3×5042141551133 (a number of 36 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 504214155113.

It is not a weakly prime, because it can be changed into another prime (504214155119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 252107077556 + 252107077557.

It is an arithmetic number, because the mean of its divisors is an integer number (252107077557).

Almost surely, 2504214155113 is an apocalyptic number.

It is an amenable number.

504214155113 is a deficient number, since it is larger than the sum of its proper divisors (1).

504214155113 is an equidigital number, since it uses as much as digits as its factorization.

504214155113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12000, while the sum is 32.

Adding to 504214155113 its reverse (311551412405), we get a palindrome (815765567518).

The spelling of 504214155113 in words is "five hundred four billion, two hundred fourteen million, one hundred fifty-five thousand, one hundred thirteen".