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50425131313057 is a prime number
BaseRepresentation
bin10110111011100100001000…
…00010100010011110100001
320121112121002002201121121011
423131302010002202132201
523102131132104004212
6255124552512500521
713423044522103324
oct1335620402423641
9217477062647534
1050425131313057
11150811a60559a6
1257a488a54a741
13221a0b9852b57
14c648373767bb
155c6a17a184a7
hex2ddc840a27a1

50425131313057 has 2 divisors, whose sum is σ = 50425131313058. Its totient is φ = 50425131313056.

The previous prime is 50425131313031. The next prime is 50425131313097. The reversal of 50425131313057 is 75031313152405.

It is an a-pointer prime, because the next prime (50425131313097) can be obtained adding 50425131313057 to its sum of digits (40).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 38953064255121 + 11472067057936 = 6241239^2 + 3387044^2 .

It is a cyclic number.

It is not a de Polignac number, because 50425131313057 - 215 = 50425131280289 is a prime.

It is not a weakly prime, because it can be changed into another prime (50425131313097) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25212565656528 + 25212565656529.

It is an arithmetic number, because the mean of its divisors is an integer number (25212565656529).

Almost surely, 250425131313057 is an apocalyptic number.

It is an amenable number.

50425131313057 is a deficient number, since it is larger than the sum of its proper divisors (1).

50425131313057 is an equidigital number, since it uses as much as digits as its factorization.

50425131313057 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 189000, while the sum is 40.

The spelling of 50425131313057 in words is "fifty trillion, four hundred twenty-five billion, one hundred thirty-one million, three hundred thirteen thousand, fifty-seven".