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50426415165473 is a prime number
BaseRepresentation
bin10110111011100110100001…
…00100000011000000100001
320121112201101120112002000122
423131303100210003000201
523102141244240243343
6255125324134130025
713423121401501304
oct1335632044030041
9217481346462018
1050426415165473
11150817a4824256
1257a4b884b0915
13221a262826039
14c64919a92b3b
155c6a905b9068
hex2ddcd0903021

50426415165473 has 2 divisors, whose sum is σ = 50426415165474. Its totient is φ = 50426415165472.

The previous prime is 50426415165407. The next prime is 50426415165563. The reversal of 50426415165473 is 37456151462405.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 30172301956624 + 20254113208849 = 5492932^2 + 4500457^2 .

It is a cyclic number.

It is not a de Polignac number, because 50426415165473 - 210 = 50426415164449 is a prime.

It is not a weakly prime, because it can be changed into another prime (50426415165403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25213207582736 + 25213207582737.

It is an arithmetic number, because the mean of its divisors is an integer number (25213207582737).

Almost surely, 250426415165473 is an apocalyptic number.

It is an amenable number.

50426415165473 is a deficient number, since it is larger than the sum of its proper divisors (1).

50426415165473 is an equidigital number, since it uses as much as digits as its factorization.

50426415165473 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12096000, while the sum is 53.

The spelling of 50426415165473 in words is "fifty trillion, four hundred twenty-six billion, four hundred fifteen million, one hundred sixty-five thousand, four hundred seventy-three".