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50432214431 is a prime number
BaseRepresentation
bin101110111101111111…
…101000010110011111
311211011201002221100202
4232331333220112133
51311241121330211
635100201214115
73433520515064
oct567577502637
9154151087322
1050432214431
111a42a741165
12993579133b
1349a9480201
142625cbcc6b
1514a27bd53b
hexbbdfe859f

50432214431 has 2 divisors, whose sum is σ = 50432214432. Its totient is φ = 50432214430.

The previous prime is 50432214421. The next prime is 50432214457. The reversal of 50432214431 is 13441223405.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 50432214431 - 222 = 50428020127 is a prime.

It is a super-2 number, since 2×504322144312 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 50432214394 and 50432214403.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (50432214421) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25216107215 + 25216107216.

It is an arithmetic number, because the mean of its divisors is an integer number (25216107216).

Almost surely, 250432214431 is an apocalyptic number.

50432214431 is a deficient number, since it is larger than the sum of its proper divisors (1).

50432214431 is an equidigital number, since it uses as much as digits as its factorization.

50432214431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11520, while the sum is 29.

Adding to 50432214431 its reverse (13441223405), we get a palindrome (63873437836).

The spelling of 50432214431 in words is "fifty billion, four hundred thirty-two million, two hundred fourteen thousand, four hundred thirty-one".