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50433005041 is a prime number
BaseRepresentation
bin101110111110000010…
…101001010111110001
311211011202121002212121
4232332002221113301
51311241322130131
635100230154241
73433530320056
oct567602512761
9154152532777
1050433005041
111a430131161
129935ab2981
1349a9699023
14262604702d
1514a28c7911
hexbbe0a95f1

50433005041 has 2 divisors, whose sum is σ = 50433005042. Its totient is φ = 50433005040.

The previous prime is 50433005033. The next prime is 50433005071. The reversal of 50433005041 is 14050033405.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 29516614416 + 20916390625 = 171804^2 + 144625^2 .

It is a cyclic number.

It is not a de Polignac number, because 50433005041 - 23 = 50433005033 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 50433004997 and 50433005015.

It is not a weakly prime, because it can be changed into another prime (50433005011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25216502520 + 25216502521.

It is an arithmetic number, because the mean of its divisors is an integer number (25216502521).

Almost surely, 250433005041 is an apocalyptic number.

It is an amenable number.

50433005041 is a deficient number, since it is larger than the sum of its proper divisors (1).

50433005041 is an equidigital number, since it uses as much as digits as its factorization.

50433005041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3600, while the sum is 25.

Adding to 50433005041 its reverse (14050033405), we get a palindrome (64483038446).

The spelling of 50433005041 in words is "fifty billion, four hundred thirty-three million, five thousand, forty-one".