Base | Representation |
---|---|
bin | 1001011001001110… |
… | …11110101110000001 |
3 | 111000111021001212202 |
4 | 10230213132232001 |
5 | 40312114423431 |
6 | 2152244002545 |
7 | 235661110103 |
oct | 45447365601 |
9 | 14014231782 |
10 | 5043514241 |
11 | 2158a28997 |
12 | b89090455 |
13 | 624b85b6c |
14 | 35bb8b573 |
15 | 1e7b9e8cb |
hex | 12c9deb81 |
5043514241 has 2 divisors, whose sum is σ = 5043514242. Its totient is φ = 5043514240.
The previous prime is 5043514183. The next prime is 5043514243. The reversal of 5043514241 is 1424153405.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3121568641 + 1921945600 = 55871^2 + 43840^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5043514241 is a prime.
Together with 5043514243, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (5043514243) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2521757120 + 2521757121.
It is an arithmetic number, because the mean of its divisors is an integer number (2521757121).
Almost surely, 25043514241 is an apocalyptic number.
It is an amenable number.
5043514241 is a deficient number, since it is larger than the sum of its proper divisors (1).
5043514241 is an equidigital number, since it uses as much as digits as its factorization.
5043514241 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9600, while the sum is 29.
The square root of 5043514241 is about 71017.7037153413. The cubic root of 5043514241 is about 1714.9221792328.
Adding to 5043514241 its reverse (1424153405), we get a palindrome (6467667646).
The spelling of 5043514241 in words is "five billion, forty-three million, five hundred fourteen thousand, two hundred forty-one".
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