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50443003201 is a prime number
BaseRepresentation
bin101110111110101000…
…110010010101000001
311211012110102001202211
4232332220302111001
51311301402100301
635101224342121
73434011311163
oct567650622501
9154173361684
1050443003201
111a43583a9a8
129939314941
1349ab789ab6
1426274ca933
1514a3700051
hexbbea32541

50443003201 has 2 divisors, whose sum is σ = 50443003202. Its totient is φ = 50443003200.

The previous prime is 50443003199. The next prime is 50443003253. The reversal of 50443003201 is 10230034405.

50443003201 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 44074803600 + 6368199601 = 209940^2 + 79801^2 .

It is a cyclic number.

It is not a de Polignac number, because 50443003201 - 21 = 50443003199 is a prime.

Together with 50443003199, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (50443004201) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25221501600 + 25221501601.

It is an arithmetic number, because the mean of its divisors is an integer number (25221501601).

Almost surely, 250443003201 is an apocalyptic number.

It is an amenable number.

50443003201 is a deficient number, since it is larger than the sum of its proper divisors (1).

50443003201 is an equidigital number, since it uses as much as digits as its factorization.

50443003201 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 22.

Adding to 50443003201 its reverse (10230034405), we get a palindrome (60673037606).

The spelling of 50443003201 in words is "fifty billion, four hundred forty-three million, three thousand, two hundred one".