Base | Representation |
---|---|
bin | 111001010110010010010000… |
… | …0001000110000011000011111 |
3 | 2110011002000012121000020222011 |
4 | 1302230210200020300120133 |
5 | 1012104221413144123033 |
6 | 4544504335052332051 |
7 | 211152412146622531 |
oct | 16254444010603037 |
9 | 2404060177006864 |
10 | 504440153114143 |
11 | 13680395a783794 |
12 | 486aba6a774027 |
13 | 1886166b7cc49c |
14 | 8c7d0685c5851 |
15 | 3d4b9a5430ccd |
hex | 1cac92023061f |
504440153114143 has 2 divisors, whose sum is σ = 504440153114144. Its totient is φ = 504440153114142.
The previous prime is 504440153114099. The next prime is 504440153114167. The reversal of 504440153114143 is 341411351044405.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-504440153114143 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 504440153114096 and 504440153114105.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (504440153117143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 252220076557071 + 252220076557072.
It is an arithmetic number, because the mean of its divisors is an integer number (252220076557072).
Almost surely, 2504440153114143 is an apocalyptic number.
504440153114143 is a deficient number, since it is larger than the sum of its proper divisors (1).
504440153114143 is an equidigital number, since it uses as much as digits as its factorization.
504440153114143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 230400, while the sum is 40.
The spelling of 504440153114143 in words is "five hundred four trillion, four hundred forty billion, one hundred fifty-three million, one hundred fourteen thousand, one hundred forty-three".
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