Base | Representation |
---|---|
bin | 100100101100111111111… |
… | …0001111110010111001111 |
3 | 122212020120101011221221011 |
4 | 1021121333301332113033 |
5 | 1130122000431144211 |
6 | 14421214233350051 |
7 | 1030306545351412 |
oct | 111317761762717 |
9 | 18766511157834 |
10 | 5044435412431 |
11 | 1675373311608 |
12 | 69578b268327 |
13 | 2a78c402820c |
14 | 13621b049b79 |
15 | 8b33d7d9921 |
hex | 4967fc7e5cf |
5044435412431 has 2 divisors, whose sum is σ = 5044435412432. Its totient is φ = 5044435412430.
The previous prime is 5044435412389. The next prime is 5044435412453. The reversal of 5044435412431 is 1342145344405.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5044435412431 - 215 = 5044435379663 is a prime.
It is a super-2 number, since 2×50444354124312 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5044435472431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2522217706215 + 2522217706216.
It is an arithmetic number, because the mean of its divisors is an integer number (2522217706216).
Almost surely, 25044435412431 is an apocalyptic number.
5044435412431 is a deficient number, since it is larger than the sum of its proper divisors (1).
5044435412431 is an equidigital number, since it uses as much as digits as its factorization.
5044435412431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 460800, while the sum is 40.
The spelling of 5044435412431 in words is "five trillion, forty-four billion, four hundred thirty-five million, four hundred twelve thousand, four hundred thirty-one".
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