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50444534773753 is a prime number
BaseRepresentation
bin10110111100001000010001…
…00100110111011111111001
320121121110011100202112202121
423132010020210313133321
523102440401400230003
6255141522132201241
713424332411563511
oct1336041044673771
9217543140675677
1050444534773753
111508945288012a
1257a85a4769221
13221bb8c774143
14c65758336841
155c72a11ebcbd
hex2de1089377f9

50444534773753 has 2 divisors, whose sum is σ = 50444534773754. Its totient is φ = 50444534773752.

The previous prime is 50444534773639. The next prime is 50444534773769. The reversal of 50444534773753 is 35737743544405.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 44248079597929 + 6196455175824 = 6651923^2 + 2489268^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-50444534773753 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 50444534773691 and 50444534773700.

It is not a weakly prime, because it can be changed into another prime (50444534723753) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25222267386876 + 25222267386877.

It is an arithmetic number, because the mean of its divisors is an integer number (25222267386877).

Almost surely, 250444534773753 is an apocalyptic number.

It is an amenable number.

50444534773753 is a deficient number, since it is larger than the sum of its proper divisors (1).

50444534773753 is an equidigital number, since it uses as much as digits as its factorization.

50444534773753 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 296352000, while the sum is 61.

The spelling of 50444534773753 in words is "fifty trillion, four hundred forty-four billion, five hundred thirty-four million, seven hundred seventy-three thousand, seven hundred fifty-three".