Base | Representation |
---|---|
bin | 101111000010010101… |
… | …010011100110010101 |
3 | 11211100210002002212211 |
4 | 233002111103212111 |
5 | 1311413240133321 |
6 | 35111321313421 |
7 | 3435363314611 |
oct | 570225234625 |
9 | 154323062784 |
10 | 50505005461 |
11 | 1a467839139 |
12 | 9956035871 |
13 | 49bb588221 |
14 | 263182a341 |
15 | 14a8d9b0e1 |
hex | bc2553995 |
50505005461 has 2 divisors, whose sum is σ = 50505005462. Its totient is φ = 50505005460.
The previous prime is 50505005437. The next prime is 50505005519. The reversal of 50505005461 is 16450050505.
50505005461 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 39035880625 + 11469124836 = 197575^2 + 107094^2 .
It is a cyclic number.
It is not a de Polignac number, because 50505005461 - 27 = 50505005333 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (50505005861) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25252502730 + 25252502731.
It is an arithmetic number, because the mean of its divisors is an integer number (25252502731).
Almost surely, 250505005461 is an apocalyptic number.
It is an amenable number.
50505005461 is a deficient number, since it is larger than the sum of its proper divisors (1).
50505005461 is an equidigital number, since it uses as much as digits as its factorization.
50505005461 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15000, while the sum is 31.
Adding to 50505005461 its reverse (16450050505), we get a palindrome (66955055966).
The spelling of 50505005461 in words is "fifty billion, five hundred five million, five thousand, four hundred sixty-one".
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