Base | Representation |
---|---|
bin | 100100110000000111101… |
… | …1001111111110010001101 |
3 | 122212212212122001222011001 |
4 | 1021200033121333302031 |
5 | 1130224213320410242 |
6 | 14424243420300301 |
7 | 1030634646462415 |
oct | 111401731776215 |
9 | 18785778058131 |
10 | 5051140013197 |
11 | 16781a3944383 |
12 | 696b406a1691 |
13 | 2a84220844c5 |
14 | 13669566d645 |
15 | 8b5d2202eb7 |
hex | 4980f67fc8d |
5051140013197 has 2 divisors, whose sum is σ = 5051140013198. Its totient is φ = 5051140013196.
The previous prime is 5051140013167. The next prime is 5051140013233. The reversal of 5051140013197 is 7913100411505.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5036047644996 + 15092368201 = 2244114^2 + 122851^2 .
It is a cyclic number.
It is not a de Polignac number, because 5051140013197 - 235 = 5016780274829 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5051140013167) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2525570006598 + 2525570006599.
It is an arithmetic number, because the mean of its divisors is an integer number (2525570006599).
Almost surely, 25051140013197 is an apocalyptic number.
It is an amenable number.
5051140013197 is a deficient number, since it is larger than the sum of its proper divisors (1).
5051140013197 is an equidigital number, since it uses as much as digits as its factorization.
5051140013197 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18900, while the sum is 37.
The spelling of 5051140013197 in words is "five trillion, fifty-one billion, one hundred forty million, thirteen thousand, one hundred ninety-seven".
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