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5051215344317 is a prime number
BaseRepresentation
bin100100110000001001111…
…1001010111001010111101
3122212220001212211012000112
41021200103321113022331
51130224342112004232
614424255111035405
71030636553001602
oct111402371271275
918786055735015
105051215344317
1116782324167aa
12696b6196bb65
132a843486b72c
141366a167c6a9
158b5d8b334b2
hex49813e572bd

5051215344317 has 2 divisors, whose sum is σ = 5051215344318. Its totient is φ = 5051215344316.

The previous prime is 5051215344313. The next prime is 5051215344349. The reversal of 5051215344317 is 7134435121505.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3050492792356 + 2000722551961 = 1746566^2 + 1414469^2 .

It is a cyclic number.

It is not a de Polignac number, because 5051215344317 - 22 = 5051215344313 is a prime.

It is a super-3 number, since 3×50512153443173 (a number of 39 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5051215344313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2525607672158 + 2525607672159.

It is an arithmetic number, because the mean of its divisors is an integer number (2525607672159).

Almost surely, 25051215344317 is an apocalyptic number.

It is an amenable number.

5051215344317 is a deficient number, since it is larger than the sum of its proper divisors (1).

5051215344317 is an equidigital number, since it uses as much as digits as its factorization.

5051215344317 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 252000, while the sum is 41.

The spelling of 5051215344317 in words is "five trillion, fifty-one billion, two hundred fifteen million, three hundred forty-four thousand, three hundred seventeen".