Base | Representation |
---|---|
bin | 1110101101000001111… |
… | …11000000000010111011 |
3 | 1210022001002120221201212 |
4 | 13112200333000002323 |
5 | 31234133240342301 |
6 | 1024031411233335 |
7 | 51333424341323 |
oct | 7264077000273 |
9 | 1708032527655 |
10 | 505212043451 |
11 | 185294033925 |
12 | 81ab65a884b |
13 | 38844bbc65b |
14 | 1a649520283 |
15 | d21d4c24bb |
hex | 75a0fc00bb |
505212043451 has 2 divisors, whose sum is σ = 505212043452. Its totient is φ = 505212043450.
The previous prime is 505212043447. The next prime is 505212043459. The reversal of 505212043451 is 154340212505.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 505212043451 - 22 = 505212043447 is a prime.
It is a super-2 number, since 2×5052120434512 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (505212043459) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 252606021725 + 252606021726.
It is an arithmetic number, because the mean of its divisors is an integer number (252606021726).
Almost surely, 2505212043451 is an apocalyptic number.
505212043451 is a deficient number, since it is larger than the sum of its proper divisors (1).
505212043451 is an equidigital number, since it uses as much as digits as its factorization.
505212043451 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24000, while the sum is 32.
Adding to 505212043451 its reverse (154340212505), we get a palindrome (659552255956).
The spelling of 505212043451 in words is "five hundred five billion, two hundred twelve million, forty-three thousand, four hundred fifty-one".
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