Base | Representation |
---|---|
bin | 100100110000100111101… |
… | …1000101110010100010011 |
3 | 122212222122102212202021212 |
4 | 1021201033120232110103 |
5 | 1130233413113440311 |
6 | 14424542123210335 |
7 | 1031003362343246 |
oct | 111411730562423 |
9 | 18788572782255 |
10 | 5052213421331 |
11 | 16786a484683a |
12 | 6971a00769ab |
13 | 2a856358454b |
14 | 13675804925d |
15 | 8b646584c8b |
hex | 4984f62e513 |
5052213421331 has 2 divisors, whose sum is σ = 5052213421332. Its totient is φ = 5052213421330.
The previous prime is 5052213421291. The next prime is 5052213421349. The reversal of 5052213421331 is 1331243122505.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5052213421331 - 234 = 5035033552147 is a prime.
It is a super-2 number, since 2×50522134213312 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5052213421351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2526106710665 + 2526106710666.
It is an arithmetic number, because the mean of its divisors is an integer number (2526106710666).
Almost surely, 25052213421331 is an apocalyptic number.
5052213421331 is a deficient number, since it is larger than the sum of its proper divisors (1).
5052213421331 is an equidigital number, since it uses as much as digits as its factorization.
5052213421331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21600, while the sum is 32.
Adding to 5052213421331 its reverse (1331243122505), we get a palindrome (6383456543836).
The spelling of 5052213421331 in words is "five trillion, fifty-two billion, two hundred thirteen million, four hundred twenty-one thousand, three hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.088 sec. • engine limits •