Base | Representation |
---|---|
bin | 100100110001001000101… |
… | …0110110011001110011001 |
3 | 122220002111120111121120202 |
4 | 1021202101112303032121 |
5 | 1130243144433312101 |
6 | 14425244021431545 |
7 | 1031042662045265 |
oct | 111422126631631 |
9 | 18802446447522 |
10 | 5053320213401 |
11 | 1679112580029 |
12 | 69744a86b5b5 |
13 | 2a86ab9728b5 |
14 | 1368210350a5 |
15 | 8b6ad80d36b |
hex | 498915b3399 |
5053320213401 has 2 divisors, whose sum is σ = 5053320213402. Its totient is φ = 5053320213400.
The previous prime is 5053320213397. The next prime is 5053320213511. The reversal of 5053320213401 is 1043120233505.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3947278874176 + 1106041339225 = 1986776^2 + 1051685^2 .
It is a cyclic number.
It is not a de Polignac number, because 5053320213401 - 22 = 5053320213397 is a prime.
It is not a weakly prime, because it can be changed into another prime (5053320213101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2526660106700 + 2526660106701.
It is an arithmetic number, because the mean of its divisors is an integer number (2526660106701).
Almost surely, 25053320213401 is an apocalyptic number.
It is an amenable number.
5053320213401 is a deficient number, since it is larger than the sum of its proper divisors (1).
5053320213401 is an equidigital number, since it uses as much as digits as its factorization.
5053320213401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10800, while the sum is 29.
Adding to 5053320213401 its reverse (1043120233505), we get a palindrome (6096440446906).
The spelling of 5053320213401 in words is "five trillion, fifty-three billion, three hundred twenty million, two hundred thirteen thousand, four hundred one".
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