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5053354234547 is a prime number
BaseRepresentation
bin100100110001001001101…
…1000100101001010110011
3122220002120221112001211012
41021202103120211022303
51130243232141001142
614425251234541135
71031043554162303
oct111422330451263
918802527461735
105053354234547
11167912a7a7683
1269745a1377ab
132a86b5a24c58
1413682576d603
158b6b17cd882
hex498936252b3

5053354234547 has 2 divisors, whose sum is σ = 5053354234548. Its totient is φ = 5053354234546.

The previous prime is 5053354234529. The next prime is 5053354234549. The reversal of 5053354234547 is 7454324533505.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 5053354234547 - 242 = 655307723443 is a prime.

Together with 5053354234549, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 5053354234495 and 5053354234504.

It is not a weakly prime, because it can be changed into another prime (5053354234549) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2526677117273 + 2526677117274.

It is an arithmetic number, because the mean of its divisors is an integer number (2526677117274).

Almost surely, 25053354234547 is an apocalyptic number.

5053354234547 is a deficient number, since it is larger than the sum of its proper divisors (1).

5053354234547 is an equidigital number, since it uses as much as digits as its factorization.

5053354234547 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15120000, while the sum is 50.

The spelling of 5053354234547 in words is "five trillion, fifty-three billion, three hundred fifty-four million, two hundred thirty-four thousand, five hundred forty-seven".