Base | Representation |
---|---|
bin | 101111000100000100… |
… | …010110001011011011 |
3 | 11211102210211222022021 |
4 | 233010010112023123 |
5 | 1311443213122021 |
6 | 35114241235311 |
7 | 3436165611313 |
oct | 570404261333 |
9 | 154383758267 |
10 | 50534114011 |
11 | 1a48220a897 |
12 | 9963932b37 |
13 | 49c460a514 |
14 | 2635646443 |
15 | 14ab6eac41 |
hex | bc41162db |
50534114011 has 2 divisors, whose sum is σ = 50534114012. Its totient is φ = 50534114010.
The previous prime is 50534113999. The next prime is 50534114021. The reversal of 50534114011 is 11041143505.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 50534114011 - 29 = 50534113499 is a prime.
It is not a weakly prime, because it can be changed into another prime (50534114021) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25267057005 + 25267057006.
It is an arithmetic number, because the mean of its divisors is an integer number (25267057006).
Almost surely, 250534114011 is an apocalyptic number.
50534114011 is a deficient number, since it is larger than the sum of its proper divisors (1).
50534114011 is an equidigital number, since it uses as much as digits as its factorization.
50534114011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1200, while the sum is 25.
Adding to 50534114011 its reverse (11041143505), we get a palindrome (61575257516).
The spelling of 50534114011 in words is "fifty billion, five hundred thirty-four million, one hundred fourteen thousand, eleven".
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