Base | Representation |
---|---|
bin | 100100110001001011011… |
… | …0011100000000011101111 |
3 | 122220002201221111201012001 |
4 | 1021202112303200003233 |
5 | 1130243341333420101 |
6 | 14425301044553131 |
7 | 1031045152032103 |
oct | 111422663400357 |
9 | 18802657451161 |
10 | 5053411623151 |
11 | 167915a134581 |
12 | 6974753b27a7 |
13 | 2a86c48993c8 |
14 | 13682d22b903 |
15 | 8b6b6867901 |
hex | 49896ce00ef |
5053411623151 has 2 divisors, whose sum is σ = 5053411623152. Its totient is φ = 5053411623150.
The previous prime is 5053411623137. The next prime is 5053411623157. The reversal of 5053411623151 is 1513261143505.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5053411623151 - 213 = 5053411614959 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 5053411623151.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5053411623157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2526705811575 + 2526705811576.
It is an arithmetic number, because the mean of its divisors is an integer number (2526705811576).
Almost surely, 25053411623151 is an apocalyptic number.
5053411623151 is a deficient number, since it is larger than the sum of its proper divisors (1).
5053411623151 is an equidigital number, since it uses as much as digits as its factorization.
5053411623151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54000, while the sum is 37.
Adding to 5053411623151 its reverse (1513261143505), we get a palindrome (6566672766656).
The spelling of 5053411623151 in words is "five trillion, fifty-three billion, four hundred eleven million, six hundred twenty-three thousand, one hundred fifty-one".
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