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505404343354403 is a prime number
BaseRepresentation
bin111001011101010011001111…
…0010110101000010000100011
32110021111011221200001101222102
41302322212132112220100203
51012221021043344320103
64550523314451401015
7211312154530502633
oct16272463626502043
92407434850041872
10505404343354403
11137045861a61119
12488268b7bb316b
131890156ab8507c
148cb39b4b766c3
153d66ad7eb2e88
hex1cba99e5a8423

505404343354403 has 2 divisors, whose sum is σ = 505404343354404. Its totient is φ = 505404343354402.

The previous prime is 505404343354357. The next prime is 505404343354459. The reversal of 505404343354403 is 304453343404505.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 505404343354403 - 238 = 505129465447459 is a prime.

It is a super-4 number, since 4×5054043433544034 (a number of 60 digits) contains 4444 as substring.

It is not a weakly prime, because it can be changed into another prime (505404343354903) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 252702171677201 + 252702171677202.

It is an arithmetic number, because the mean of its divisors is an integer number (252702171677202).

Almost surely, 2505404343354403 is an apocalyptic number.

505404343354403 is a deficient number, since it is larger than the sum of its proper divisors (1).

505404343354403 is an equidigital number, since it uses as much as digits as its factorization.

505404343354403 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10368000, while the sum is 47.

Adding to 505404343354403 its reverse (304453343404505), we get a palindrome (809857686758908).

The spelling of 505404343354403 in words is "five hundred five trillion, four hundred four billion, three hundred forty-three million, three hundred fifty-four thousand, four hundred three".