Base | Representation |
---|---|
bin | 10110111110111100100010… |
… | …00001101110100111010011 |
3 | 20121221200222000200011012012 |
4 | 23133132101001232213103 |
5 | 23111032102202241202 |
6 | 255254205300253135 |
7 | 13434326600633645 |
oct | 1337362101564723 |
9 | 217850860604165 |
10 | 50541313321427 |
11 | 151164a5840435 |
12 | 58032b36a11ab |
13 | 2228043a43876 |
14 | c6a2d95c6895 |
15 | 5c9a676ec152 |
hex | 2df79106e9d3 |
50541313321427 has 2 divisors, whose sum is σ = 50541313321428. Its totient is φ = 50541313321426.
The previous prime is 50541313321409. The next prime is 50541313321511. The reversal of 50541313321427 is 72412331314505.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 50541313321427 - 232 = 50537018354131 is a prime.
It is not a weakly prime, because it can be changed into another prime (50541313321627) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25270656660713 + 25270656660714.
It is an arithmetic number, because the mean of its divisors is an integer number (25270656660714).
Almost surely, 250541313321427 is an apocalyptic number.
50541313321427 is a deficient number, since it is larger than the sum of its proper divisors (1).
50541313321427 is an equidigital number, since it uses as much as digits as its factorization.
50541313321427 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 302400, while the sum is 41.
The spelling of 50541313321427 in words is "fifty trillion, five hundred forty-one billion, three hundred thirteen million, three hundred twenty-one thousand, four hundred twenty-seven".
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