Base | Representation |
---|---|
bin | 10110111110111100100010… |
… | …00001101110101000100111 |
3 | 20121221200222000200011022022 |
4 | 23133132101001232220213 |
5 | 23111032102202242021 |
6 | 255254205300253355 |
7 | 13434326600634125 |
oct | 1337362101565047 |
9 | 217850860604268 |
10 | 50541313321511 |
11 | 151164a5840501 |
12 | 58032b36a125b |
13 | 2228043a4390c |
14 | c6a2d95c6915 |
15 | 5c9a676ec1ab |
hex | 2df79106ea27 |
50541313321511 has 2 divisors, whose sum is σ = 50541313321512. Its totient is φ = 50541313321510.
The previous prime is 50541313321427. The next prime is 50541313321537. The reversal of 50541313321511 is 11512331314505.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-50541313321511 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (50541313321571) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25270656660755 + 25270656660756.
It is an arithmetic number, because the mean of its divisors is an integer number (25270656660756).
Almost surely, 250541313321511 is an apocalyptic number.
50541313321511 is a deficient number, since it is larger than the sum of its proper divisors (1).
50541313321511 is an equidigital number, since it uses as much as digits as its factorization.
50541313321511 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 27000, while the sum is 35.
The spelling of 50541313321511 in words is "fifty trillion, five hundred forty-one billion, three hundred thirteen million, three hundred twenty-one thousand, five hundred eleven".
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