Base | Representation |
---|---|
bin | 100100110001100011100… |
… | …0011100000000101100111 |
3 | 122220011211100201121111212 |
4 | 1021203013003200011213 |
5 | 1130302021101431233 |
6 | 14425513243222035 |
7 | 1031104211465525 |
oct | 111430703400547 |
9 | 18804740647455 |
10 | 5054221123943 |
11 | 16795350744a2 |
12 | 69766051791b |
13 | 2a87c34c7864 |
14 | 1368a894b315 |
15 | 8b712969a48 |
hex | 498c70e0167 |
5054221123943 has 2 divisors, whose sum is σ = 5054221123944. Its totient is φ = 5054221123942.
The previous prime is 5054221123927. The next prime is 5054221123961. The reversal of 5054221123943 is 3493211224505.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5054221123943 - 24 = 5054221123927 is a prime.
It is a Sophie Germain prime.
It is a self number, because there is not a number n which added to its sum of digits gives 5054221123943.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5054221123043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2527110561971 + 2527110561972.
It is an arithmetic number, because the mean of its divisors is an integer number (2527110561972).
Almost surely, 25054221123943 is an apocalyptic number.
5054221123943 is a deficient number, since it is larger than the sum of its proper divisors (1).
5054221123943 is an equidigital number, since it uses as much as digits as its factorization.
5054221123943 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 259200, while the sum is 41.
The spelling of 5054221123943 in words is "five trillion, fifty-four billion, two hundred twenty-one million, one hundred twenty-three thousand, nine hundred forty-three".
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