Base | Representation |
---|---|
bin | 1001011010100110… |
… | …10011110111010101 |
3 | 111001021212211000201 |
4 | 10231103103313111 |
5 | 40323040112432 |
6 | 2153334140501 |
7 | 236160553222 |
oct | 45523236725 |
9 | 14037784021 |
10 | 5055004117 |
11 | 2164466459 |
12 | b90ab1731 |
13 | 6273798c7 |
14 | 35d4dc949 |
15 | 1e8bbdee7 |
hex | 12d4d3dd5 |
5055004117 has 2 divisors, whose sum is σ = 5055004118. Its totient is φ = 5055004116.
The previous prime is 5055004081. The next prime is 5055004133. The reversal of 5055004117 is 7114005505.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5047960401 + 7043716 = 71049^2 + 2654^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5055004117 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5055005117) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2527502058 + 2527502059.
It is an arithmetic number, because the mean of its divisors is an integer number (2527502059).
Almost surely, 25055004117 is an apocalyptic number.
It is an amenable number.
5055004117 is a deficient number, since it is larger than the sum of its proper divisors (1).
5055004117 is an equidigital number, since it uses as much as digits as its factorization.
5055004117 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3500, while the sum is 28.
The square root of 5055004117 is about 71098.5521441893. The cubic root of 5055004117 is about 1716.2234741957.
The spelling of 5055004117 in words is "five billion, fifty-five million, four thousand, one hundred seventeen".
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