Base | Representation |
---|---|
bin | 10110111111001100110100… |
… | …00100101101101100010011 |
3 | 20121222112112020202010221102 |
4 | 23133212122010231230103 |
5 | 23111203003042033434 |
6 | 255302212533415015 |
7 | 13435056326154221 |
oct | 1337463204555423 |
9 | 217875466663842 |
10 | 50550055033619 |
11 | 1511a181258169 |
12 | 5804b3319a46b |
13 | 2228b07b3c02b |
14 | c6a8c85a5b11 |
15 | 5c9dc9da907e |
hex | 2df99a12db13 |
50550055033619 has 2 divisors, whose sum is σ = 50550055033620. Its totient is φ = 50550055033618.
The previous prime is 50550055033603. The next prime is 50550055033651. The reversal of 50550055033619 is 91633055005505.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 50550055033619 - 24 = 50550055033603 is a prime.
It is a super-3 number, since 3×505500550336193 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (50550055033679) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25275027516809 + 25275027516810.
It is an arithmetic number, because the mean of its divisors is an integer number (25275027516810).
Almost surely, 250550055033619 is an apocalyptic number.
50550055033619 is a deficient number, since it is larger than the sum of its proper divisors (1).
50550055033619 is an equidigital number, since it uses as much as digits as its factorization.
50550055033619 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1518750, while the sum is 47.
The spelling of 50550055033619 in words is "fifty trillion, five hundred fifty billion, fifty-five million, thirty-three thousand, six hundred nineteen".
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