Base | Representation |
---|---|
bin | 10110111111010010011111… |
… | …00110111011010000110001 |
3 | 20121222211101111122220212022 |
4 | 23133221033212323100301 |
5 | 23111230222233200233 |
6 | 255303435052241225 |
7 | 13435224650544401 |
oct | 1337511746732061 |
9 | 217884344586768 |
10 | 50553100678193 |
11 | 151204a4463aa3 |
12 | 5805643170215 |
13 | 22291a1b15399 |
14 | c6aad6c90801 |
15 | 5ca007467398 |
hex | 2dfa4f9bb431 |
50553100678193 has 2 divisors, whose sum is σ = 50553100678194. Its totient is φ = 50553100678192.
The previous prime is 50553100678187. The next prime is 50553100678229. The reversal of 50553100678193 is 39187600135505.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 43235464335424 + 7317636342769 = 6575368^2 + 2705113^2 .
It is a cyclic number.
It is not a de Polignac number, because 50553100678193 - 222 = 50553096483889 is a prime.
It is not a weakly prime, because it can be changed into another prime (50553100678153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25276550339096 + 25276550339097.
It is an arithmetic number, because the mean of its divisors is an integer number (25276550339097).
Almost surely, 250553100678193 is an apocalyptic number.
It is an amenable number.
50553100678193 is a deficient number, since it is larger than the sum of its proper divisors (1).
50553100678193 is an equidigital number, since it uses as much as digits as its factorization.
50553100678193 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3402000, while the sum is 53.
The spelling of 50553100678193 in words is "fifty trillion, five hundred fifty-three billion, one hundred million, six hundred seventy-eight thousand, one hundred ninety-three".
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