Base | Representation |
---|---|
bin | 101111000101001110… |
… | …000000100011101111 |
3 | 11211111011012000210011 |
4 | 233011032000203233 |
5 | 1312013134032421 |
6 | 35120211154051 |
7 | 3436522005061 |
oct | 570516004357 |
9 | 154434160704 |
10 | 50553424111 |
11 | 1a4920a9853 |
12 | 996a2a5927 |
13 | 49c860b908 |
14 | 2638031731 |
15 | 14ad2624e1 |
hex | bc53808ef |
50553424111 has 2 divisors, whose sum is σ = 50553424112. Its totient is φ = 50553424110.
The previous prime is 50553424091. The next prime is 50553424139. The reversal of 50553424111 is 11142435505.
50553424111 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 50553424111 - 25 = 50553424079 is a prime.
It is a super-2 number, since 2×505534241112 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (50553424151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25276712055 + 25276712056.
It is an arithmetic number, because the mean of its divisors is an integer number (25276712056).
Almost surely, 250553424111 is an apocalyptic number.
50553424111 is a deficient number, since it is larger than the sum of its proper divisors (1).
50553424111 is an equidigital number, since it uses as much as digits as its factorization.
50553424111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12000, while the sum is 31.
Adding to 50553424111 its reverse (11142435505), we get a palindrome (61695859616).
The spelling of 50553424111 in words is "fifty billion, five hundred fifty-three million, four hundred twenty-four thousand, one hundred eleven".
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