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50553424111 is a prime number
BaseRepresentation
bin101111000101001110…
…000000100011101111
311211111011012000210011
4233011032000203233
51312013134032421
635120211154051
73436522005061
oct570516004357
9154434160704
1050553424111
111a4920a9853
12996a2a5927
1349c860b908
142638031731
1514ad2624e1
hexbc53808ef

50553424111 has 2 divisors, whose sum is σ = 50553424112. Its totient is φ = 50553424110.

The previous prime is 50553424091. The next prime is 50553424139. The reversal of 50553424111 is 11142435505.

50553424111 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 50553424111 - 25 = 50553424079 is a prime.

It is a super-2 number, since 2×505534241112 (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (50553424151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25276712055 + 25276712056.

It is an arithmetic number, because the mean of its divisors is an integer number (25276712056).

Almost surely, 250553424111 is an apocalyptic number.

50553424111 is a deficient number, since it is larger than the sum of its proper divisors (1).

50553424111 is an equidigital number, since it uses as much as digits as its factorization.

50553424111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12000, while the sum is 31.

Adding to 50553424111 its reverse (11142435505), we get a palindrome (61695859616).

The spelling of 50553424111 in words is "fifty billion, five hundred fifty-three million, four hundred twenty-four thousand, one hundred eleven".