Base | Representation |
---|---|
bin | 101111000101001110… |
… | …010101101000010101 |
3 | 11211111011100102011211 |
4 | 233011032111220111 |
5 | 1312013144313141 |
6 | 35120213101421 |
7 | 3436522514521 |
oct | 570516255025 |
9 | 154434312154 |
10 | 50553510421 |
11 | 1a492158687 |
12 | 996a327871 |
13 | 49c863bc9b |
14 | 2638054d81 |
15 | 14ad27cd81 |
hex | bc5395a15 |
50553510421 has 2 divisors, whose sum is σ = 50553510422. Its totient is φ = 50553510420.
The previous prime is 50553510401. The next prime is 50553510451. The reversal of 50553510421 is 12401535505.
50553510421 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 49512480196 + 1041030225 = 222514^2 + 32265^2 .
It is a cyclic number.
It is not a de Polignac number, because 50553510421 - 213 = 50553502229 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (50553510401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25276755210 + 25276755211.
It is an arithmetic number, because the mean of its divisors is an integer number (25276755211).
Almost surely, 250553510421 is an apocalyptic number.
It is an amenable number.
50553510421 is a deficient number, since it is larger than the sum of its proper divisors (1).
50553510421 is an equidigital number, since it uses as much as digits as its factorization.
50553510421 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15000, while the sum is 31.
The spelling of 50553510421 in words is "fifty billion, five hundred fifty-three million, five hundred ten thousand, four hundred twenty-one".
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