Base | Representation |
---|---|
bin | 10110111111010110101100… |
… | …10101011111000110001101 |
3 | 20122000001020000220201100221 |
4 | 23133223112111133012031 |
5 | 23111244334410434131 |
6 | 255304451235351341 |
7 | 13435334655326053 |
oct | 1337532625370615 |
9 | 218001200821327 |
10 | 50555361030541 |
11 | 15121454365194 |
12 | 5805b74152551 |
13 | 22294721b8193 |
14 | c6ac6d15c1d3 |
15 | 5ca0dab06411 |
hex | 2dfad655f18d |
50555361030541 has 2 divisors, whose sum is σ = 50555361030542. Its totient is φ = 50555361030540.
The previous prime is 50555361030533. The next prime is 50555361030553. The reversal of 50555361030541 is 14503016355505.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 36900643668100 + 13654717362441 = 6074590^2 + 3695229^2 .
It is a cyclic number.
It is not a de Polignac number, because 50555361030541 - 23 = 50555361030533 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (50555361030841) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25277680515270 + 25277680515271.
It is an arithmetic number, because the mean of its divisors is an integer number (25277680515271).
Almost surely, 250555361030541 is an apocalyptic number.
It is an amenable number.
50555361030541 is a deficient number, since it is larger than the sum of its proper divisors (1).
50555361030541 is an equidigital number, since it uses as much as digits as its factorization.
50555361030541 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 675000, while the sum is 43.
The spelling of 50555361030541 in words is "fifty trillion, five hundred fifty-five billion, three hundred sixty-one million, thirty thousand, five hundred forty-one".
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