Base | Representation |
---|---|
bin | 101111001010000101… |
… | …101100100010110101 |
3 | 11211200211221011122111 |
4 | 233022011230202311 |
5 | 1312200043143221 |
6 | 35132250331021 |
7 | 3441533340544 |
oct | 571205544265 |
9 | 154624834574 |
10 | 50635131061 |
11 | 1a524236459 |
12 | 9991729a71 |
13 | 4a0c518c18 |
14 | 2644c2015b |
15 | 14b5501be1 |
hex | bca16c8b5 |
50635131061 has 2 divisors, whose sum is σ = 50635131062. Its totient is φ = 50635131060.
The previous prime is 50635131049. The next prime is 50635131101. The reversal of 50635131061 is 16013153605.
50635131061 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 44307724036 + 6327407025 = 210494^2 + 79545^2 .
It is a cyclic number.
It is not a de Polignac number, because 50635131061 - 27 = 50635130933 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (50635131761) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25317565530 + 25317565531.
It is an arithmetic number, because the mean of its divisors is an integer number (25317565531).
Almost surely, 250635131061 is an apocalyptic number.
It is an amenable number.
50635131061 is a deficient number, since it is larger than the sum of its proper divisors (1).
50635131061 is an equidigital number, since it uses as much as digits as its factorization.
50635131061 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8100, while the sum is 31.
Adding to 50635131061 its reverse (16013153605), we get a palindrome (66648284666).
The spelling of 50635131061 in words is "fifty billion, six hundred thirty-five million, one hundred thirty-one thousand, sixty-one".
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