Base | Representation |
---|---|
bin | 10111000001110001100100… |
… | …11110010011111000011101 |
3 | 20122021222211220200022200111 |
4 | 23200320302132103320131 |
5 | 23114130132333221042 |
6 | 255411002204530021 |
7 | 13444340341330123 |
oct | 1340706236237035 |
9 | 218258756608614 |
10 | 50638511226397 |
11 | 15153743498016 |
12 | 581a0bab50911 |
13 | 2234263b715c3 |
14 | c70cba439913 |
15 | 5cc355936517 |
hex | 2e0e32793e1d |
50638511226397 has 2 divisors, whose sum is σ = 50638511226398. Its totient is φ = 50638511226396.
The previous prime is 50638511226349. The next prime is 50638511226437. The reversal of 50638511226397 is 79362211583605.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 25942173475716 + 24696337750681 = 5093346^2 + 4969541^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-50638511226397 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (50638511226307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25319255613198 + 25319255613199.
It is an arithmetic number, because the mean of its divisors is an integer number (25319255613199).
Almost surely, 250638511226397 is an apocalyptic number.
It is an amenable number.
50638511226397 is a deficient number, since it is larger than the sum of its proper divisors (1).
50638511226397 is an equidigital number, since it uses as much as digits as its factorization.
50638511226397 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16329600, while the sum is 58.
The spelling of 50638511226397 in words is "fifty trillion, six hundred thirty-eight billion, five hundred eleven million, two hundred twenty-six thousand, three hundred ninety-seven".
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